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Exact values and exact upper bounds for families of integers with arithmetic progression intersections (Erdős Problem #272)

Let $t(N)$ be the largest $t$ for which there exist distinct sets $A_1,\dots,A_t \subseteq \{1,\dots,N\}$ such that $A_i \cap A_j$ is a nonempty arithmetic progression for all $i \neq j$ (Erdos Problem #272).

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2026
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arxiv.org/abs/2607.23004CC-BY-4.0
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Abstract

Let t(N) be the largest t for which there exist distinct sets A_1,\dots,A_t \subseteq {1,\dots,N} such that A_i \cap A_j is a nonempty arithmetic progression for all i \neq j (Erdos Problem #272). Simonovits and Sos proved t(N)=O(N^2) and conjectured \binom{N}{2}+1 is best possible; Szabo disproved this by a construction giving t(N) \geq \binom{N}{2}+1+\lfloor(N-1)/4\rfloor, proved the asymptotics t(N)=N^2/2+O(N^{5/3}(\log N)^3), and asked whether t(N)=\binom{N}{2}+O(N) and whether some element lies in all sets of any extremal family (the kernel question). We determine t(N) exactly for all 3 \leq N \leq 12 by exhaustive computation: in this entire range Szabo's lower bound is exact, and we conjecture that t(N)=\binom{N}{2}+1+\lfloor(N-1)/4\rfloor for every N. Towards the matching upper bound we prove, for every N, that Szabo's bound is the exact maximum over all families with a common element (starred families). The proof combines a self-contained ``defect-one'' counting inequality for staircase regions with a new structural theorem: every non-progression member of such a family contains a bad pair that no other member can share. Consequently the sharpened conjecture reduces to a single remaining statement, namely Szabo's kernel conjecture that some element lies in all sets of an extremal family, and we prove first structural constraints on putative non-starred extremal families.